Question

Shelly's scores on her first two tests in Algebra were 72 and 89. What will she need to make on the third test to have an average of at least 80?

Answer 1

\[\huge \frac{72 + 89 + x}{3} >80\]
\[\huge 161 + x> 240\]
\[\huge x > 240 - 161\]
\[\huge x > 79\]
got it @kena ?

Answer 2

Average = Total Marks/Number of tests

Answer 3

thanks(;

Answer 4

Actually a score of 79 will give an average of 80, \[x \ge79\]