Question

Solve the equation using the quadratic formula.

2x2 = -12x - 3

A.https://study.ashworthcollege.edu/access/content/group/e4bcd776-749a-49f8-8403-365cad5d3c31/GM%20Exam%206/images/f1q5g1.jpg

Answer 1

B. https://study.ashworthcollege.edu/access/content/group/e4bcd776-749a-49f8-8403-365cad5d3c31/GM%20Exam%206/images/f1q5g2.jpg

Answer 2

C. https://study.ashworthcollege.edu/access/content/group/e4bcd776-749a-49f8-8403-365cad5d3c31/GM%20Exam%206/images/f1q5g3.jpg

Answer 3

D. https://study.ashworthcollege.edu/access/content/group/e4bcd776-749a-49f8-8403-365cad5d3c31/GM%20Exam%206/images/f1q5g4.jpg

Answer 4

This one is B?

Answer 5

i can do this sum.

Answer 6

I got B not to sure...

Answer 7

i got C.

Answer 8

Arrange the equation in the form ax^2 + bx +c = 0
2x^2 = -12x - 3
2x^2 + 12x + 3 = 0
Use quadratic formula:
\[x= \frac{-b\pm \sqrt{b^2 - 4ac}}{2a}\] Put a = 2, b=12 c = 3 into the formula.
\[x= \frac{-12\pm \sqrt{12^2 - 4(2)(3)}}{2(2)}\] \[x= \frac{-12\pm \sqrt{144 - 24}}{2(2)}\] \[x= \frac{-12\pm \sqrt{120}}{2(2)}\] \[x= \frac{-12\pm \sqrt{2^2 \times 30}}{2(2)}\] \[x= \frac{-12\pm 2\sqrt{30}}{2(2)}\] \[x= \frac{2(-6\pm \sqrt{30})}{2(2)}\] Now you should be able to simplify it and get the answer.

Answer 9

Okay then I get this https://study.ashworthcollege.edu/access/content/group/e4bcd776-749a-49f8-8403-365cad5d3c31/GM%20Exam%206/images/f1q5g3.jpg

Answer 10

Its C :/

Answer 11

I got it right ?

Answer 12

Yup :)

Answer 13

YES :) thank you.

Answer 14

Welcome!~