Question

factoring by groupings:
1.2x raise to 2-x +2xy-y
2.15xy+20y-12x-16
can you help me .

Answer 1

Is 1. \[2x^2-x+2xy-y\]
Please confirm then I can help :-)

Answer 2

the ans. is:
(3x+4)(5y-4)

Answer 3

@marryrizabolofer I don't think that is the answer....can you show your work.

Answer 4

For question 1,
\[2x^2-x +2xy-y\]\[=x(2x-1) +y(2x-1)\]\[=(x+y)(2x-1)\]

For question 2,
15xy+20y-12x-16
= 5y ( 3x + 4) - 4 ( 3x+4)
= ...?
Just take out the common factor and group the rest of the terms, like what I've done for question 1.