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is P(-4,0) Q(0,2) M(-2,1) and the required line is x=-2
Sorry but could you teach me how?
\[x-2y=-4\] find the y intercept (0,y) by setting x=0 find the x-intercept (x,0) by setting y=0
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to find the mid point between P and Q just take the average of each co-ordinate
Ok thanks SO much ^^
vertical lines will have the form x=k, where k is the x intecept
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