Question

The length of a rectangle exceeds its width by 4 meters and its perimeter is 68 meters. Find the dimensions of the rectangle.

Answer 1

http://www.algebra.com/algebra/homework/Rectangles/Rectangles.faq.question.341706.html

Answer 2

32 and 36

Answer 3

answer^^^^ link

Answer 4

Let us assume that the length is x + 4 and the width is x.

\( \color{Black}{\Rightarrow 2(l + b) = P}\)
\( \color{Black}{\Rightarrow 2(x + 4 + x ) = P}\)
\( \color{Black}{\Rightarrow 2(2x + 4) = P}\)

Answer 5

let the two consecytive even number be x and x+2
x+x2=150
2x+2=150
2x=148
x=74
the two numbers are 74and 76

Answer 6

*consecutive

Answer 7

here is a simple solution:

given that there are two quantities involved, divide the perimeter by two
(68/2=34)

then divide the exceed of the other number to the other number by 2.
(4/2=2)

then, add and subtract 2 from 34
(34-2=32)
(34+2=36)

answers: 32 and 36

Answer 8

the answer is 74 and 76

Answer 9

that's for the first question. lolz

Answer 10

:D