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some Projectiles are thrown with 0
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state your answer in terms of \[a=\frac{v_{0}^2}{4g}\]
is the answer \[s = -\nu _{o}^{2}\sin ^{2}\theta / 2g\] ?
thats right \[y=\frac{v_{0}^2 \sin^2 \theta}{2g}\] but can u change it to x,y (cartesian coordinates)
@Vaidehi09 \[\sin \theta = \frac{y}{\sqrt{x^2+y^2}}\]
oh. yes u can do that. that'll be just playing with the terms.
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