Question

finding the factor by groupings
abc + 2c + 3ab + 6
ad- 3d - 3ac - 9c

Answer 1

ok !
\[\huge{abc+2c+3ab+6}\]
\[\huge{c(ab+2)+3(ab+2)}\]

You can apply the inverse of distributive property here :

\[\huge{ab+ac=a(b+c)}\]
can u simplify that?

Answer 2

uhm ( ab+2 ) ( c + 3 ) is this the answer ?

Answer 3

HELLO

Answer 4

yes u r right can u do the second one ?

Answer 5

yes !!

Answer 6

i'm time ! sorry..

Answer 7

bye & thanks for helping me :)