Question

In △JKL, solve for x.



17.32

38.16

66.73

74.89

Answer 1

Do you know about SOH CAH TOA?

Answer 2

correct me if im wrong. sin over hypotenues, adjacent over hypotenours and tan over adjacent. is that correct?

Answer 3

close.

Answer 4

sin=opp/hyp cos=adj/hyp tan=opp/adj

Answer 5

To find out x you may apply tangent thingy ..

\[\tan 27^o = \frac{opposite}{adjacent} = \frac{34}{x}\]

Answer 6

now. look at the triangle, what two side are going to be used?

Answer 7

opp and adj, like additi_singh said

Answer 8

so, we will use TOA

Answer 9

tan=opp/adjacent

Answer 10

tan27(34

Answer 11

enter that into ur scientific calculator

Answer 12

sorry, it actually 27tan(34 in the calculator

Answer 13

i got 18.21

Answer 14

nvm, thats what u do for cos, and sin. sorry, let me fix it

Answer 15

ok, i switched it around.

Answer 16

34tan(27, lol. eneter that into ur calc

Answer 17

17.32

Answer 18

there u go, sorry about before

Answer 19

its fine and thanks

Answer 20

np