Mathematics
21 Online
OpenStudy (anonymous):
In △JKL, solve for x.
17.32
38.16
66.73
74.89
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OpenStudy (anonymous):
OpenStudy (hang254):
Do you know about SOH CAH TOA?
OpenStudy (anonymous):
correct me if im wrong. sin over hypotenues, adjacent over hypotenours and tan over adjacent. is that correct?
OpenStudy (hang254):
close.
OpenStudy (hang254):
sin=opp/hyp cos=adj/hyp tan=opp/adj
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OpenStudy (anonymous):
To find out x you may apply tangent thingy ..
\[\tan 27^o = \frac{opposite}{adjacent} = \frac{34}{x}\]
OpenStudy (hang254):
now. look at the triangle, what two side are going to be used?
OpenStudy (hang254):
opp and adj, like additi_singh said
OpenStudy (hang254):
so, we will use TOA
OpenStudy (hang254):
tan=opp/adjacent
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OpenStudy (hang254):
tan27(34
OpenStudy (hang254):
enter that into ur scientific calculator
OpenStudy (hang254):
sorry, it actually 27tan(34 in the calculator
OpenStudy (anonymous):
i got 18.21
OpenStudy (hang254):
nvm, thats what u do for cos, and sin. sorry, let me fix it
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OpenStudy (hang254):
ok, i switched it around.
OpenStudy (hang254):
34tan(27, lol. eneter that into ur calc
OpenStudy (anonymous):
17.32
OpenStudy (hang254):
there u go, sorry about before
OpenStudy (anonymous):
its fine and thanks
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OpenStudy (hang254):
np