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Mathematics 21 Online
OpenStudy (anonymous):

In △JKL, solve for x. 17.32 38.16 66.73 74.89

OpenStudy (anonymous):

OpenStudy (hang254):

Do you know about SOH CAH TOA?

OpenStudy (anonymous):

correct me if im wrong. sin over hypotenues, adjacent over hypotenours and tan over adjacent. is that correct?

OpenStudy (hang254):

close.

OpenStudy (hang254):

sin=opp/hyp cos=adj/hyp tan=opp/adj

OpenStudy (anonymous):

To find out x you may apply tangent thingy .. \[\tan 27^o = \frac{opposite}{adjacent} = \frac{34}{x}\]

OpenStudy (hang254):

now. look at the triangle, what two side are going to be used?

OpenStudy (hang254):

opp and adj, like additi_singh said

OpenStudy (hang254):

so, we will use TOA

OpenStudy (hang254):

tan=opp/adjacent

OpenStudy (hang254):

tan27(34

OpenStudy (hang254):

enter that into ur scientific calculator

OpenStudy (hang254):

sorry, it actually 27tan(34 in the calculator

OpenStudy (anonymous):

i got 18.21

OpenStudy (hang254):

nvm, thats what u do for cos, and sin. sorry, let me fix it

OpenStudy (hang254):

ok, i switched it around.

OpenStudy (hang254):

34tan(27, lol. eneter that into ur calc

OpenStudy (anonymous):

17.32

OpenStudy (hang254):

there u go, sorry about before

OpenStudy (anonymous):

its fine and thanks

OpenStudy (hang254):

np

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