Simplify the rational expression. State any excluded values. x-2/x^2+3x-10 A. x^2 B. x+5, where x is not equal to -5 C. 1/x2 where x is not equal to -2 D. 1/x+5 where x is not equal to -5
@chadandtricia_2009 could you rewrite the problem in a better form.
\[x-2divx^2+3x-10\]
factor the denominator: = ( x -2)(x + 5)
the x-2 ' s cancel out giving 1 / (x + 5)
so now you should know the correct option
so it is D
yep
thanks can you help me if I need anymore help?
when x = -5 the denominator = 0 x = -5 is the excluded value
sure
Simplify the rational expression. State any excluded values. x^2-36/6-x A. –x – 6; where x is not equal to 6 B. x + 6; where x is not equal to -6 C. 1/x-6 ; where x is not equal to 6 D. 1/x+6 ; where x is not equal to -6
the numerator is difference of 2 sqaures:
I think the answr is B
= (x - 6)(x + 6) ------------- = - (x + 6) = -x - 6 -(x - 6)
what value of x will make the denominator zero?
-6
no its 6 ; -(6 - 6) = 0
so that elimates a and c
so it is b or d
nope its A
ok thanks again
note what i had to do in oreder to simplify i had to change 6 - x to -(x - 6) in order to cancel out the x - 6 in the numerators |dw:1341420697713:dw|
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