Simplify the rational expression. State any excluded values.
x-2/x^2+3x-10
A. x^2
B. x+5, where x is not equal to -5
C. 1/x2 where x is not equal to -2
D. 1/x+5 where x is not equal to -5
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OpenStudy (anonymous):
@chadandtricia_2009 could you rewrite the problem in a better form.
OpenStudy (anonymous):
\[x-2divx^2+3x-10\]
OpenStudy (anonymous):
factor the denominator:
= ( x -2)(x + 5)
OpenStudy (anonymous):
the x-2 ' s cancel out giving 1 / (x + 5)
OpenStudy (anonymous):
so now you should know the correct option
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OpenStudy (anonymous):
so it is D
OpenStudy (anonymous):
yep
OpenStudy (anonymous):
thanks can you help me if I need anymore help?
OpenStudy (anonymous):
when x = -5 the denominator = 0
x = -5 is the excluded value
OpenStudy (anonymous):
sure
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OpenStudy (anonymous):
Simplify the rational expression. State any excluded values.
x^2-36/6-x
A. –x – 6; where x is not equal to 6
B. x + 6; where x is not equal to -6
C. 1/x-6 ; where x is not equal to 6
D. 1/x+6 ; where x is not equal to -6