Ask your own question, for FREE!
Mathematics 8 Online
OpenStudy (anonymous):

Factor completely: 6x^2-xy-12y^2

OpenStudy (anonymous):

\[6 x^2-x y-12 y^2=(2 x-3 y) (3 x+4 y) \]

OpenStudy (anonymous):

How did you get that answer?

OpenStudy (theviper):

\[6x^2-xy-12y^2\]\[\implies6x^2-4xy+3xy-12y^2\]\[\implies2x(3x-2y)+3y(x-4y)\]\[(2x+3y)(3x-2y)(x-4y)\]

OpenStudy (anonymous):

Why did it go from -xy to -4xy + 3xy?

OpenStudy (anonymous):

Sorry, I'm not too good with factoring when the first term is greater than 1.

OpenStudy (theviper):

wait

OpenStudy (theviper):

use this www.wolframalpha.com

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!