Question

find the rectangular coordinates of the point with polar coordinates (-2, 5pi/6)

Answer 1

\[Given: r=-2; \theta=5\pi/6\]

Answer 2

We know the following:\[x=rcos \theta; y=rsin \theta \]

Answer 3

\[x=-2\cos(5\pi/6)=-2(-\sqrt{3}/2)=\sqrt{3}\]
and
\[y=-2(1/2)=-1\]

Answer 4

So (-2, 5pi/6) in rect coor. is (sqrt(3),-1)

Any questions?

Answer 5

perfect!! THANK YOU!!!