The area of a rectangle is the product of width and length. If a rectangle has length 15mthe square root of 13 times m. and width the square root of 9 times m., which of the following is the area of the rectangle?

Question

tennistar · Answer

I got |dw:1341442616593:dw|now what?

anonymous · Answer

Is this the problem?
Find the area if:
length = $15m\sqrt{13}m$
width = $\sqrt{9}m$

tennistar · Answer

yes

anonymous · Answer

Can you possibly draw the problem as it is or if it's on the computer, screenshot it?

tennistar · Answer

attachment

anonymous · Answer

$$A = 15m\sqrt{13 \times 3^{2} \times m^{2}}$$Can you solve it now? Just take the squared parts outside of the radical.

tennistar · Answer

so a = 15m * 3^2 8m^2 sqrt13

anonymous · Answer

Well, what's the $\sqrt{9}$?

tennistar · Answer

please just give me an answer, I am on a time limit

anonymous · Answer

Sorry, but it's against CoC. Actually, we would've been done a minute ago if you just answered that, but here's the next step.
$$15(3)(m)(m)\sqrt{13}$$