Question

Solve for x: square root of (x+4)=x-2.
I'm trying to do this problem and I think I did something wrong but can't tell what it is. Right now I have: x^2-x=0

Answer 1

Is it √ ( x +4) = x -2 ?

Answer 2

Yeah

Answer 3

Have you ( x-2)² = ....

Answer 4

Yes. And, I have \[x+4=x^2+4\]

Answer 5

( x-2)² = x² - 4x + 4

Answer 6

Since ( x-2)² = ( x -2) ( x -2)

Answer 7

Oooooooooooh. Right. I always forget to FOIL...

Answer 8

Can you get this result?
( x-2)² = x² - 4x + 4

Answer 9

Yes

Answer 10

After working it out, I now have\[x^2-5x\]

Answer 11

Does x=0?

Answer 12

x ( x - 5) = 0

Answer 13

Can you solve for x?

Answer 14

x=0, 5?

Answer 15

Is that my final answer or can I only have 1?

Answer 16

Alright. Thank you! :)

Answer 17

@alienshe I forgot to check x-2 ≥ 0 => x ≥ 2
Thus only one solution x = 5 accepted