Question

In the below system, solve for y in the first equation.

x – 3y = –6
2x – 7y = 10

one thirdx + 2

negative one thirdx + 6

–x + 2

negative one thirdx + 2

Answer 1

\[y=2+x/3\]

Answer 2

oh thanks!

Answer 3

\[x-3y=-6\]
Subtract x from both sides
\[-3y=-6-x\]
divide by neg. 3
\[y=(-6-x)/-3\]
Remember the -3 must go with the -6 and -x so it becomes
\[y=2+(1/3)x\]

Answer 4

oh ok thank you so much! :)