Question

(x^2-8/10x^5+25x)
Lim-> infinity

Answer 1

Evaluating that limit results in f(x)=0. As x^5 as x goes to infinity is a larger magnitude of infinity than x^2 as x goes to infinite (the expression on the numerator) the denominator will become larger and larger and the numerator smaller and smaller which results in values like (.00000001 etc) closer and closer to 0.