Question

The figure shows a triangular park ABC. The area DEFC is cordoned off by putting barricades on the sides DE and EF.



What is the total length of the barricades DE and EF?

90 feet

108 feet

36 feet

120 feet

Answer 1

ABC and BEF are similiar triangles (because DC is parallel to EF, and this makes all the angles in 2 triangles equal)

to find EF, using similiar triangles properties

AC/AB = EF/EB
90/150=EF/120

to find DE, which is equal to CF, you have to find FB

CB/AB = FB/EB
180/150 = FB/120

then CB-FB = CF = DE

Answer 2

108?

Answer 3

yes

Answer 4

thanks