Question

hi what is the factor of 2x^2-3x-9?

Answer 1

2x^2 - 3x - 9

break down the middle term

2x^2 + 6x - 3x - 9

group them

(2x^2 + 6x) - (3x + 9)

factor out

2x(x + 3) - 3(x+3)

do you see it now?

Answer 2

\[x^2-3x-9=0\]
\[x^2-6x+3x-9=0\]
\[2x(x-3)+3(x-3)=0\]
now you try to simplify.

Answer 3

you can use the quadratic formula i.e
\[-b \pm \sqrt{b ^{2}-4ac}/2a\]
here a=2
b=-3
c=-9
put the values of a, b and c in equation and you'll get your answer

Answer 4

thanks for helping me

Answer 5

factor of 2x+8

Answer 6

28X+7

Answer 7

we have to make the first term of these sums.

Answer 8

I CANNOT SOLVE THAT ONE

Answer 9

wait i am doing.

Answer 10

hi what is the factor of 8x^3-216

Answer 11

2x+342

Answer 12

\[First Term= (Middle Term)^2/4*(Last Term)\]

Answer 13

thanks,but im not asking what is the procedure im asking is what is the solution?

Answer 14

kantutan

Answer 15

gago ka talaga

Answer 16

oo nga pala tuloy ung sa e
nglish

Answer 17

tar
a abano
Joke :D

Answer 18

factor of 8x^3-216
\[8x(x^2-27)=0\]
\[8x=0 \]
\[x=0\]
or \[x^2-27=0\]
\[x^2=27\]
\[x=\sqrt{27}\]

Answer 19

abano add mo ko sa fwend m!!

Answer 20

(x-6)(x+3)

Answer 21

@danny_dumond Please don't post only answers as that's against the Code of Conduct: http://openstudy.com/code-of-conduct

Answer 22

well find

something like

(cx+a) (dx+b) to = 2x^2-3x-9

Answer 23

Gosh sorry! :P