Question

Quadratic Equation


1.)(2/x)^2-4=7
2.)1/2x+3/2x^2-5=4

Answer 1

and the question is...?

Answer 2

identify A,B,C,

Answer 3

\[\left(\frac{2}{x}\right)^2-4=7\]\[\frac{4}{x^2}=11\]\[4=11x^2\]\[11x^2-4=0\]

now your first equation is of the form \[ax^2+by+c=0\]
you can apply the quadratic formula

\[x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\]