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OpenStudy (anonymous):
What a b c?
OpenStudy (anonymous):
quadratic equation
OpenStudy (anonymous):
15+2x-x^2
a-x^2
b-2x
c-15
OpenStudy (anonymous):
Just foil it out
OpenStudy (anonymous):
formula?
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sam (.sam.):
@DylanH you forgot the 2
OpenStudy (anonymous):
what 2?
mathslover (mathslover):
\[\huge{(5-x)(3+x)=2}\]
\[\huge{5(3)+5x-3x+x^2=2}\]
\[\huge{15+2x+x^2=2}\]
The general form of a quadratic equation is \(\large{ax^2+bx+c=0}\)
compare both equations : can u do this now ?
mathslover (mathslover):
Note u can also write \(\huge{15+2x+x^2=2}\) as :
\[\huge{x^2+2x+15=2}\]
OpenStudy (anonymous):
ohhh my bad
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OpenStudy (anonymous):
ok tnx
OpenStudy (anonymous):
what is c pls. i knew a=1 b= 2 c=?
OpenStudy (anonymous):
@mathslover PLS ANSWER
OpenStudy (anonymous):
13..
mathslover (mathslover):
a : 1 , b: 2 and c : 15
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OpenStudy (anonymous):
isnt it 13? cause you will transpose 2 to the left side 15-2 =13
mathslover (mathslover):
oh yes sorry u r right
OpenStudy (anonymous):
@mathslover pls answer may last question (2/x)^2-4=7 find a b and c again pls
mathslover (mathslover):
\[\huge{\frac{4}{x^2}-4=7}\]
\[\huge{\frac{4}{x^2}-11=0}\]
\[\huge{\frac{4-11x^2}{x^2}=0}\]
\[\huge{4-11x^2=0}\]
\[\huge{11x^2-4+0=0}\]
a = 11 , b = -4 , c =0 :)
OpenStudy (anonymous):
thanks
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OpenStudy (anonymous):
if the hat cost 9.53 and the sale taxes was7% how much did rosa pay for the hat ?
OpenStudy (anonymous):
$10.20
mathslover (mathslover):
@lanceglojames first of all welcome to openstudy
I request you to post the questions as there in the bar of You have an open question : ask ... dont post in the other student's question .thanks!
OpenStudy (anonymous):
25 childern will attend the birthday party . if each child gets 15 party favors and there are 75 favors in each box . how many boxs should raymond buy ?