Question

test

Answer 1

which of the following best summarizes how to solve for the varible x and which rule was used to do so

Answer 2

2x/3=-2
2x=-6
x=-3

Answer 3

a: multiply by 3 over 2 on both sides of the equation by the addition prop. of equality?

Answer 4

The addition property of equality states that you can add something to both sides of an equation and it will stay balanced.

Answer 5

Original Problem:
\(\large\frac{2}{3}\dot\ x = -2\)

Write x over 1:
\(\large\frac{2}{3}\dot\ \frac{x}{1} = -2\)

Multiply the left side:
\(\large\frac{2x}{3} = \frac{-2}{1}\)

Cross Multiply:
\(2x = -6\)

Divide by sides by 2:
\(\frac{2x}{2}=\frac{-6}{2}\)

Solution:
\(x=-3\)