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Express in logarithmic form for the base. 4^2=16
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\( \color{Black}{\Rightarrow a^b = c \Longrightarrow \log_ac = b}\)
Use this example.
Here: \(4 = a\) \(2 = b\) \(16 = c\)
alright i got log(4) 16=2
Yes.
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yeah of course u r right 100% So as parth said.\[\huge{4^2}=16.\]\[\huge{\color{blue}\log_4\color{green}{16}=\color{red}2}\]
what about with this express in exponential form log(3)9=2
just reverse the process:)
could you put it into an equation like above so i can work from it
\( \color{Black}{\Rightarrow \log _a b = c \Longrightarrow a^c = b}\)
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