Question

Find the indefinite integral involving secant and tangent.

Answer 1

\[\int\limits (\sec(7x-27))^2 dx\]

Answer 2

u = 7x-27

du = 7dx

1/7du = dx

Answer 3

\[\int\limits \sec^2 (u) du \]

Answer 4

= tan(u) + c

Answer 5

= tan(7x-27) + c?

Answer 6

dont forget 1/7

Answer 7

1/7tan(7x-27) + c

Answer 8

yeah I just realized that :P yu

Answer 9

ty*