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Mathematics 8 Online
OpenStudy (anonymous):

P(x)=x^2+2x^2-4x-5. How many negative zeros are in this polynomial function?

OpenStudy (anonymous):

do you mean roots?

OpenStudy (anonymous):

no square roots

OpenStudy (anonymous):

2/3 - sqrt(19)/3 is your negative root

OpenStudy (anonymous):

Just so you know @Diogo roots, solutions, zeros, all the same thing...

OpenStudy (anonymous):

@Calcmathlete , here in portugal we call it "zeros". But i heard everyone here using the name root so i though it was a diferent thing. To answer your question, there is one negative root in that polynomial

OpenStudy (anonymous):

Can you tell me where it is?

OpenStudy (anonymous):

Already did: 2/3 - sqrt(19)/3

OpenStudy (anonymous):

My bad ... should be x^3 in stead of the 2 power

OpenStudy (anonymous):

ohhh. That changes everything. Just a sec

OpenStudy (anonymous):

It has 2 negative roots. x = -1 OR x = 1/2 (-1-sqrt(21)) ~ -2.79128784747792

OpenStudy (anonymous):

I do not understand why you are squaring(roots) when I need zeros and multiplicities? You may be right on the number of zero of this function, but I am not sure.

OpenStudy (anonymous):

Sorry. That english is too advanced for me. You better ask anyone else then. But i am correct in one thing. Your polynomial has 2 negative roots

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