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Solve 2(4 – b) = 2 − b –(b − 6).
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is it b –(b − 6). or b(b − 6).
b-(b-6)
ok then so distribute 2(4-b) = 8-2b then the 2-b-b-6 is 2-6 = -4 so we getr 8-2b = -4 -8 from both sides -12 = -2b divide -2 on each b = 6
these are the answers??? b = 0 b = -4 This is an identity and is true for all real numbers. There is no solution.
actually I mesed up.
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2--6 = 8 -2b = 0 b = 0
they are = to each other.
8-2b = 8-2b
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