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solve the equation please 3\2b+8=20
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I hope that this is the question : \[\huge{\frac{3}{2b}+8=20}\] is it ?
it is but the b is beside the 3/2 haha
u mean : \[\huge{\frac{3b}{2}+8=20}\]
\[\frac{3}{2}b + 8 = 20\]\[\frac32b = 12\]\[b = \frac{12}{1}\times\frac{2}{3}\]\[b = ?\]This works because dividing by a fraction is the same as multiplying by it's reciprocal.
do i cross mulitiply to figure out what b =? Calcmathlete?
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