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Arithmetic Sequence : If Sn = -441 for the series 19 + 15 + 11 + ... + tn, find n.
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What is the last term you are given??
i think it is n or \(\huge{t_n}\)
You are asking to whom??
Remember : \[\Huge{S_n=\frac{n}{2}{2n+(n-1)d}}\]
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I think the Sum is given and we have to find the n..
Formula for sum is: \[\huge \color{green}{ S_n = \frac{n}{2}(2a + (n-1)d)}\]
Oh yes sorry
i put n there
Here, You have \(S_n = -441\) \(a = 19\) \(d = 15 -19 = -4\) Just plug in these values in the formula and then solve for n...
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