A father is twice as old as his son, six years ago father was thrice as old as his son. What is the age of the son?
f=2s f+6=3s. -> f=3s-6 3s-6=2s s=6
F = 2S.. 6 years ago , F = 3( S - 6) therefore 2S = 3S - 18.. S = 18 years.. @student92 : shoud`t be it like this ??
oh sorry i though he write six years later
But the answer is 6 years...
?
6 is right , u mean to say ?
yeah
@mathslover , @hero, @ParthKohli : Guys little confusion here.. can u please help ??
A father is twice as old as his son, six years ago father was thrice as old as his son. What is the age of the son? this is the question : Let son's age be x and father's will be : 2x six years ago there age was : x-6 and 2x-6 and given (2x-6)=3(x-6) 2x-6=3x-18 2x-3x=-12 x=12
2x = 24
father's age = 24 son's age =12 u can verify this also
alright its 12 then..
ohkey, i missed to subtract father`s age by 6 !! thanks @mathslover ; yes brother.. this is the answer..
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