a tank contains 100 gal of water. brine enters the tank at the rate of 3 gpm. the mixture, thoroughly stirred, leaves the tank at the rate of 2 gpm. if the concentration of the brine at the end of 20 minutes is to be 2 lb/gal, what should be the concentration of the brine entering the tank?
@amistre64 would you happen to know this cheese?
i think i recall it
yay!
in-out = total amount that stays right?
i believe so?
42.
input - output = accumulation
does that mean same thing?
yes
i see i see
how do we calculate salinity?
is the brine 100% coming in?
what does salinity mean?
brine is salt water; salt is a saline solution ....
well the amt of brine coming in is represented by c1 the amt of water coming in is r1
so c1 is 100% salt i believe
you have lbs/gal to figure out, but i dont see where you can determine how many lbs there is coming and going to start of with
here is the formula \[\large r_1 c_1 - r_2 [\frac{Q}{V_o + (r_1 - r_2)t}] = \frac{dQ}{dt}\]
after 20 minutes tho, i would assume there is about 120 gallons in the tank; but i cant see a way of calculating lbs to gallons without knowing the ratio of the incoming brine
i remember my teacher doing something like linear DE...does that help?
it might, but doesnt jog any memories :) at any rate, i have to get back to pulling files for statistical analysises. Good luck :)
uhhmm okay..good luck to you too :)
well i guess no one can solve this here.....
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