Help Please!!

A student mixed 4.00mL of 1.02x10^(-1) M Fe(NO3)3 with 100.00mL of 1.98*10^(-4) M KSCN, using 5.0*10^(-1) M HNO3 as the solvent for both solutions, and found the absorbance of the resulting equilibrium mixture to be 0.253. Given these data, calculate the following: 1. [Fe*] 2. [SCN*] 3.[Fe*] + [SCN*] 4.[Fe*][SCN*] 5.A([Fe*] + [SCN*]) 6.A / ([Fe*][SCN*]) 7. (A([Fe*] + [SCN*]))/([Fe*][SCN*])

Question

Help Please!!

A student mixed 4.00mL of 1.02x10^(-1) M Fe(NO3)3 with 100.00mL of 1.98*10^(-4) M KSCN, using 5.0*10^(-1) M HNO3 as the solvent for both solutions, and found the absorbance of the resulting equilibrium mixture to be 0.253. Given these data, calculate the following: 1. [Fe*] 2. [SCN*] 3.[Fe*] + [SCN*] 4.[Fe*][SCN*] 5.A([Fe*] + [SCN*]) 6.A / ([Fe*][SCN*]) 7. (A([Fe*] + [SCN*]))/([Fe*][SCN*])