Question

Find the equation of the line through (-4, 6) and perpendicular to y = -3x + 4

Answer 1

slope of y=-3x + 4 is equal to -3
therefore slope of desired line is 1/3 (m1 * m2 = -1 for perpendicular lines)
therefore the equation of desired line is
y-(-4) = 1/3(x-6) => y+4 = 1/3(x-6)
=> 3y + 12 = x- 6
=> x-3y = 18