Question

Is there anyone who can help me with Calculus

Answer 1

yup...go ahead

Answer 2

im sure it depends?

Answer 3

zzr0ck3r: depends on what?

Answer 4

Depends on the question. Please ask specific questions, anyone who can help you will surely do so.

Answer 5

there is a calculus question that no one in hhere can do:) so it depends on what you need for help.

Answer 6

find the equation of the secant line that passes through the graph of f(x)=x^3 at x=-3 and x=4 .

Answer 7

Unless I'm mistaken, calculus methods aren't necessary for that. Simply find the coordinates of f(x)=x^3 at x=-3 and x=4, and then find the line through the two points.

Answer 8

where is the calculus

Answer 9

ok thanks