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Write the equation of a line in slope-intercept form that is perpendicular to the line y=3/5x-1 and passes through the point (-9, 4).
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what is the slope of a perpendicular line?
i dont know thts all i have and im confused
it's the negative reciprocal.
-9
negative reciprocal of 3x/5 is not -9
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then?
y=mx+b where m is the slope. Since the perpendicular slope is the negative reciprocal, you flip the fraction representing the slope and you multiply it by -1.
so would it be -5/3x-11
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