The number of computers sold by BCC depends on the dollar amount, x, that they spend on advertising. How many computers will they sell by spending $80,000 on advertising? Round to the nearest whole number and do not include units in your answer.

N(x) = 100 + 20 ln(0.25x)

Question

The number of computers sold by BCC depends on the dollar amount, x, that they spend on advertising. How many computers will they sell by spending $80,000 on advertising? Round to the nearest whole number and do not include units in your answer.

N(x) = 100 + 20 ln(0.25x)

anonymous · Answer

Plug x = $80,000 in
N ( 80,000 ) = 100 + 20 ln 20,000

Can you finish it?

anonymous · Answer

not at all would I minus 100 on both sides.

anonymous · Answer

ln = 2.718

anonymous · Answer

Take ln ( 20,000 )
Multiply by 20
Add 100

anonymous · Answer

ok and my answer would be 400100

anonymous · Answer

the answer was 298

anonymous · Answer

Number of computers is 298

anonymous · Answer

I have another question.

anonymous · Answer

Learn this one before you opening the new post!