Ask your own question, for FREE!
Mathematics 13 Online
OpenStudy (anonymous):

i really need help!! Suppose that you were saving money over 5 years to use in a purchase later. You have $1000 to put in the savings. After surveying several banks for savings plans, you found these options. "A" stands for the amount you will have in the bank after x years. • Option A: Your money would receive simple interest at the end of 5 years. The formula is A = 1000 + 1000(0.05) x. • Option B: Your money will be compounded continuously. The formula is A = (1000)(2.71828)(0.05 x).• Option D: Buy a US Savings Bond. Buy at $1000 now • Option C: You will invest in a CD (Certificate of Deposit) compounded Calculate each of these. You can find this by substituting x = 5 in each formula. Note that there is no formula in the US Savings Bonds option, just the amount. Post a response with your answers to the following questions. 1.Show the calculations for A, B, and C. 2.What is the order of Options A, B, C, and D, listing the option which gives the greatest amount at the end of 5 years to the least? 3.Which option gave you the greatest amount at the end of the five years? 4.What was the amount you calculated with this option?

OpenStudy (anonymous):

Option A: 1000+1000(0.05)= 1050$ Option B: (1000)(2.71828)(0.05(5))=679.57 (hmm...I'm assuming that you add this nmber to 1000, so 1679.57$) Option C: (1000)(1.05)(5)=5250$ Option D: 1267$ _____________________________ thats what i did so far

OpenStudy (valpey):

I don't see the description of D, but here is what I am interpreting (note that with C I am compounding annually): \[A=$1000+$1000*.05 = $1050\] \[B=$1000e^{.05t} =$1000*e^{.25}=$1000*1.284=$1284\] \[C=1000*(1.05)^t = $1000*1.276=$1276\]

OpenStudy (valpey):

The exponents are the big piece of the question you seem to be missing.

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!