Question

Create your own third degree polynomial that when divided by x + 2 has a remainder of –4

Answer 1

Poly(ax^3+bx^2+cx+d)+4=(x+2)*Poly(ex^2+fx+g)

Answer 2

If you want to keep it simple let e =1 and f and g = 0 then:
Poly(ax^3+bx^2+cx+d)+4=(x+2)*x^2=x^3+2x^2
That would imply a=1 and b=2 and c=0
Then d = -4

Answer 3

So \[x^3+2x^2-4\] is one such polynomial.