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OpenStudy (anonymous):
3x+2y=12, for y
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mathslover (mathslover):
\[\huge{3x+2y=12}\] \[\huge{2y=12-3x}\] \[\huge{y=\frac{12-3x}{2}}\] got it ?
OpenStudy (anonymous):
i think so, so am I dividing 2 into 12-3x
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