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In forward bias in a pn junction diode is changed from 0.7V to 2.2V then forward current changes by 1.5 mA. The forward resistance is
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I believe it would be:\[\frac{2.2V-0.7V}{1.5x10^{-3}A}=1kOhm\]
Are you sure? I am asking this because you have mentioned "I believe" in your reply.
It seems like a simple ohms law problem to me...someone else can chime in if it's incorrect.
May be you are correct but lets see what others think..
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