Question

LGBADERIVATIVE:

\[\huge xe^y = x - y\]

Answer 1

im thinking left side is product rule...?

Answer 2

yes and chain rule

Answer 3

\[\huge xe^y y' + e^y = 1 - y'?\]

Answer 4

yup

Answer 5

\[\huge xe^y y' + y' = 1 - e^y\]
\[\huge y'(xe^y + 1) = 1 - e^y\]
\[\huge y' = \frac{1-e^y}{xe^y + 1}\]

Answer 6

that right?

Answer 7

@Mimi_x3 ?

Answer 8

yeah thats right

Answer 9

thanks! :D

Answer 10

ur welcome