Mathematics
22 Online
OpenStudy (anonymous):
a) find the value or values of x that make the denominator 0
b) keeping the restrictions in mind, solve the equation
(1/x-4) - (5/x+2) = (6/x^2+x-6)
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OpenStudy (anonymous):
are all the parenthisis on their correct place?
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
no...
OpenStudy (anonymous):
parenthesis means its all one expression inside
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OpenStudy (anonymous):
then you dont have the parenthisis on the correct place. Cant help you again
OpenStudy (anonymous):
so if i say (1/x-4) it looks like this |dw:1341675899392:dw|
OpenStudy (anonymous):
if i meant what you said it would read (1/x)+4
OpenStudy (anonymous):
why dont you just type like this like a normal person:
1/(x-4) - 5/(x+2) = 6/(x^2+x-6)
OpenStudy (anonymous):
you know what the problem is now can you help?
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OpenStudy (anonymous):
im on it. just a sec
OpenStudy (anonymous):
the books given answers were a) -2,4 and b) 0
OpenStudy (anonymous):
i understand the -2,4 but not the 0
OpenStudy (anonymous):
in which grade are you?
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OpenStudy (anonymous):
sophomore college
OpenStudy (anonymous):
do you already know what imaginary numbers are?
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
hmm.. your answers are for the left side of the equation, right? cause if X = -3 or x= 2 on the right side, the dominator is also 0
OpenStudy (anonymous):
oh sorry the book answer is no solution, not zero
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OpenStudy (anonymous):
no -3 works for the right side
OpenStudy (anonymous):
9-6-8 isnt 0
OpenStudy (anonymous):
9+6-8*
OpenStudy (anonymous):
(-3)^2 -3-6
9 -9 = 0
-3 works
OpenStudy (anonymous):
i fear ive wasted your time, i accidentally entered the wrong numbers for the last 3 numbers on the right side looking at another problem
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OpenStudy (anonymous):
the right side is actualy 6/(x^2-2x-8)
OpenStudy (anonymous):
sorry
OpenStudy (anonymous):
ohhh so that only changes.... EVERYTHING
a) x= 4 x= -2
b) no solution
OpenStudy (anonymous):
hahahha
OpenStudy (anonymous):
feel free to ignore may questions in the future
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OpenStudy (anonymous):
:p
OpenStudy (anonymous):
can you explain how its no solution though?
OpenStudy (anonymous):
well how can you find that without graphing nine lines?
OpenStudy (anonymous):
try to solve for X and you'll see you wont get anywhere
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OpenStudy (anonymous):
i ended up with 4
OpenStudy (anonymous):
ohhh but it cant be 4!
OpenStudy (anonymous):
so its undefined.. got it
OpenStudy (anonymous):
gottcha