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Find the domain and range of a real function f(x) =1/(1-x^2)?
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domain = R-[-1 , 1] is that correct
then wat is the range??
hw to find it
solve for x the equation \[ y=f(x)=\frac{1}{1-x^2} \] you'll get something like x=g(y) and do for this whatever you did to find the domain of f
\[ 1 \over 1 - x^2\]
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what values of x is not possible? and what outcome is not possible?
0 is not possible
|dw:1341678680439:dw|
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