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\(1+\sin x+ \sin^2 x +...... to \infty\)=4+3\(\sqrt3\), (\(0
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use trigonometric series a=1 q=sin x lql<1
Geometric****
\[\frac{1}{1-\sin x}=4+3\sqrt3\]But none of the options seem to satisfy this.
o.O
The closest to the answer seems to be \(\pi\)/3..
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that gives sin x=0.891
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