Question

multiply::

(2sqrt3+5)(3sqrt3-7)

Answer 1

So you distribute as you would before (a+b)(c+d) So when you distribute 2sqrt3 to the (3sqrt3-7) what do you have?
2sqrt3(3sqrt3-7)= 2sqrt3 * 3sqrt3 -2sqrt3 * -7=6*3 - 14sqrt3=18 -14 sqrt3 Now distribute 5(3sqrt3 - 7)= 15 sqrt 3-35 You add the results 18-14 sqrt3 + 15 sqrt3 -35=-31+(-14+15)sqrt3=-31+sqrt3

Answer 2

do you understand?
recall that \[\sqrt3*\sqrt3=3\]

Answer 3

i understand...but the answer choices are:

-35-34sqrt3
-35+6sqrt3
-17+sqrt3
-17+29sqrt3

Answer 4

I caught my mistake
"You add the results 18-14 sqrt3 + 15 sqrt3 -35" after this it should be
=18-35+(-14+15)sqrt3=-17+sqrt3

Answer 5

there we go thanks youre the best!

Answer 6

you are welcome!