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Mathematics 21 Online
OpenStudy (anonymous):

Factor completely: 21x^3y^4 + 15x2y2 − 12xy^3 3xy(7x2y3 + 5x − 4y) 3xy(7x2y + 5x − 4y^2) 3xy^2(7x^2y + 5x − 4y) 3xy^2(7x^2y^2 + 5x − 4y)

OpenStudy (helder_edwin):

what is the lowest power of x and y? what is the greatest common divisor of 21, 15 and 12? once you get these, you factor them!

OpenStudy (anonymous):

idk?

OpenStudy (helder_edwin):

you have \[ \LARGE 21x^3y^4+12x^2y^2-12xy^3 \] what is the lowest power of x and y?

OpenStudy (anonymous):

2?

OpenStudy (helder_edwin):

this is the lowest power of y! what about x?

OpenStudy (anonymous):

1?

OpenStudy (helder_edwin):

great this mean you can factor \[ \LARGE xy^2 \] from the expresion! what is the greatest common divisor of the coefficients?

OpenStudy (anonymous):

umm....im confused agin.

OpenStudy (anonymous):

sorry.

OpenStudy (anonymous):

21x^3y^4 + 15x2y2 − 12xy^3= 3xy^2( 7 x^2 y^2 + 5 x - 4 y) 4th choice

OpenStudy (anonymous):

thank you..!

OpenStudy (helder_edwin):

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