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Mathematics 19 Online
OpenStudy (anonymous):

find a plane perpendicular to vector(2,3,4) and passing through the (0,-2,1)

OpenStudy (anonymous):

2(x-0)+3(y+2)+4(z-1)=0

OpenStudy (anonymous):

would you mind explain it to me?

OpenStudy (anonymous):

think of plane equation like the dot ptoduct of vectors (2,3,4) and (x-0,y+2,z-1). So all (x,y,z) that are perpendicular to (2,3,4) will define a plane

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