Question

rationalize the denominator:

sqrt -16 / (1+i) + (6+3i)

Answer 1

is this
\[ \Large \frac{\sqrt{-16}}{1+i}+(6+3i) \]
right?

Answer 2

yes but the (6+3i) is is with the 1+i. its all on the botom

Answer 3

\[\frac{\sqrt{-16}}{(1+i) + (6+3i)}\]
\[\frac{4i}{1+i + 6 + 3i}\]
\[\frac{4i}{7 + 4i}\]
\[\frac{4i}{7+4i} \times \frac{7-4i}{7-4i}\]

Answer 4

got it?

Answer 5

could you break it down further please?