Question

Divide and express the result in standard form:
8i/(4-3i)

Answer 1

\[\frac{8i}{4-3i} \times \frac{4+3i}{4+3i}\]
\[\frac{8i(4+3i)}{16 - 9i^2}\]
\[\frac{8i(4+3i)}{16 - 9(-1)}\]
\[\frac{8i(4+3i)}{16 + 9}\]
\[\frac{8i(4+3i)}{25}\]
simplify by distribution