Question

PLz help:)
@mathslover @Hero

Answer 1

K i am going to help you !

Answer 2

multiply both numerator and denominator with \[\sqrt{3} -1\]

Answer 3

Rationalize

Answer 4

I tried but failed :(
@mathslover

Answer 5

Alright, rationalize and you will get it.

\[\frac{\sqrt{3}-1}{\sqrt{3}+1}=\frac{\sqrt{3}-1}{\sqrt{3}+1}*\frac{\sqrt{3}-1}{\sqrt{3}-1}= \frac{3+2\sqrt{3}+1}{3-1}=\frac{2\sqrt{3}-4}{2}=\sqrt{3}-2\]

Answer 6

then the ans tat will come, compare with a+b[\sqrt{3}\]

Answer 7

Typo

\[\frac{\sqrt{3}-1}{\sqrt{3}+1}=\frac{\sqrt{3}-1}{\sqrt{3}+1}*\frac{\sqrt{3}-1}{\sqrt{3}-1}= \frac{3-2\sqrt{3}+1}{3-1}=\frac{-2\sqrt{3}-4}{2}=-\sqrt{3}-2\]

Answer 8

\[\Huge{\color{green}{\mathbb{Answer:-}}}\]\[\LARGE{\color{blue}{a=2, b=-1}}\]

Answer 9

yes right

Answer 10

TheViper is right.

Answer 11

Aparently, I made two typos.

Answer 12

k! thanx @mathslover @jlvm