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Mathematics 52 Online
OpenStudy (anonymous):

Find the probability of the following five-card poker hands from a 52-card deck. In poker, aces are either high or low. Two pair (2 cards of one value, 2 of another value)

OpenStudy (anonymous):

OpenStudy (anonymous):

22464 is incorrect :-/ completely lost

OpenStudy (valpey):

the number of ways to pick five cards out of 52 is \[\frac{52!}{47!*5!}\] The number of ways to pick two pair is 13 possible first pairs with 6 suit combinations times 12 possible second pairs with 6 suit combinations divided by two because 5588 is the same as 8855 times 11 possible extra cards times 4 possible suits.

OpenStudy (valpey):

so the numerator is 11*4*13*6*12*6/2 and the denominator is 52*51*50*49*48/(5*4*3*2)

OpenStudy (valpey):

You can do a lot of cancellation before you get to the ultimate answer.

OpenStudy (anonymous):

5148

OpenStudy (kropot72):

The answer should be a probability equivalent to approximately 4.75%

OpenStudy (valpey):

Try cancellation from here: \[\frac{4*11*6*13*6*6}{52*51*5*49*4}\]

OpenStudy (zarkon):

are you trying to calculate the probability of 2-pair ...2 cards of one rank and another 2 cards of the same but different rand from the first 2 and a 5th card of a rank different than the other 4?

OpenStudy (anonymous):

did you get an answer yet that you like?

OpenStudy (anonymous):

i can't say i like any of these choices hmmm

OpenStudy (valpey):

Yes, one of the answers is very close, but not correct. Maybe the deck is missing a card :)

OpenStudy (anonymous):

Thanks guys I got it and yes I was really close ;)

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