Find the probability of the following five-card poker hands from a 52-card deck. In poker, aces are either high or low. Two pair (2 cards of one value, 2 of another value)
22464 is incorrect :-/ completely lost
the number of ways to pick five cards out of 52 is \[\frac{52!}{47!*5!}\] The number of ways to pick two pair is 13 possible first pairs with 6 suit combinations times 12 possible second pairs with 6 suit combinations divided by two because 5588 is the same as 8855 times 11 possible extra cards times 4 possible suits.
so the numerator is 11*4*13*6*12*6/2 and the denominator is 52*51*50*49*48/(5*4*3*2)
You can do a lot of cancellation before you get to the ultimate answer.
5148
The answer should be a probability equivalent to approximately 4.75%
Try cancellation from here: \[\frac{4*11*6*13*6*6}{52*51*5*49*4}\]
are you trying to calculate the probability of 2-pair ...2 cards of one rank and another 2 cards of the same but different rand from the first 2 and a 5th card of a rank different than the other 4?
did you get an answer yet that you like?
i can't say i like any of these choices hmmm
Yes, one of the answers is very close, but not correct. Maybe the deck is missing a card :)
Thanks guys I got it and yes I was really close ;)
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