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Mathematics 20 Online
OpenStudy (theviper):

Please help:)

OpenStudy (theviper):

What is the value of x, y, & z respectively on simplifying the equations \[2x+3y=0,3y+4z=14,2x+4z=26??\]

OpenStudy (theviper):

@campbell_st

OpenStudy (theviper):

wait I got sorry for tagging:)

OpenStudy (campbell_st):

add equations 1 and 2 will give 2x + 6y + 4z = 14 or re-writing it 2x + 4z + 6y = 14 equation 3 says 2x + 4z = 26 substituting 26 + 6y = 14 or 6y = -12 y = -2 substitute it into the 1st equation to find x 2x + 3(-2) = 0 2x = 6 x = 3 to find z use 2x + 4z = 26 2(3) + 4z = 26 4z = 20 z = 5 so the solutions are x = 3, y = -2 ans z =5

OpenStudy (theviper):

thank u

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