Question

Plz help:)

Answer 1

If the difference of the squares of two numbers is 45, the square of the smaller number is 4 times the larger number, then the numbers are??

Answer 2

@campbell_st

Answer 3

give me the equations plz

Answer 4

@satellite73 I bow to thee

Answer 5

hmm
\[x^2-y^2=45\]
\[y^2=4x\]

Answer 6

k then

Answer 7

and so
\[x^2-4x=45\]
\[(x-2)^2+45+4=49\]
\[x-2=7\]
\[x=9\]

Answer 8

ok... let x be the larger number and y the smaller number

then you know

\[x^2 - y^2 = 45\]

and \[y^2 = 4x\]

make the substitution so that you have an equation in y

it will be a quadratic that needs to be solved

Answer 9

yes k! thanx @satellite73 :)

Answer 10

& @campbell_st

Answer 11

thanx all of u:)